Practice question

Given: A magnetic dipole of moment 0.45 A m² is in a uniform field of 0.6 T at 45° . What is the torque on it? These values define the system as per NCERT data. Formula: Torque is tau = m B sinθ. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Given: m = 0.45 A m², B = 0.6 T, θ = 45°, sin 45° = frac1sqrt2 approx 0.707 . Substitute: tau = 0.45 × 0.6 × 0.707 approx 0.19089 N m approx 0.191 N m . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.