Practice question
Question
A hydraulic system has a small piston (0.005m2) and a large piston (0.025m2). If 80N is applied on the small piston, what force does the large piston exert?
Explanation
Pascal’s law: P = F1A1 = F2A2. F2 = F1×A2A1. F1 = 80N, A1 = 0.005m2, A2 = 0.025m2. F2 = 80×0.0250.005 = 80×5 = 400N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 400 N. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
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