Practice question
Question
A hydraulic press applies 200N on a small piston of area 0.01m2. What force is exerted by a large piston of area 0.04m2?
Explanation
Pascal’s law: P = F1A1 = F2A2. F2 = F1×A2A1. F1 = 200N, A1 = 0.01m2, A2 = 0.04m2. F2 = 200×0.040.01 = 200×4 = 800N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 800 N. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
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