Practice question
Question
A gas at 11 atm and 90^circ C in a 10 L container is cooled isochorically to 30^circ C . What is the final pressure?
Explanation
**Work and heat** both energy transfer modes, work organized, e.g., lifting weight, compressing gas, electrical current, heat random due to temperature difference, work can be completely converted to heat via friction, but heat cannot be completely converted to work (second law), energy transfer modes include work (mechanical, electrical) and heat (conduction, convection, radiation). For isochoric: (P₁)/(T₁) = (P₂)/(T₂) . P₁ = 11 atm , T₁ = 90 + 273 = 363 K , T₂ = 30 + 273 = 303 K . (11)/(363) = (P₂)/(303) ⇒ P₂ = (11 × 303)/(363) ≈ 9.18 atm . Using first law ΔU = Q - W, W =
Discussion
Comments
Please log in to join the discussion.
Login to commentNo comments yet. Be the first to start the discussion.