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A gas absorbs 1200 J of heat at constant pressure, and its volume increases by 0.5 L against 2 atm. What is Δ U ? (1 atm·L = 101.325 J)

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1200 J 1098.7 J Correct 1301.3 J 998.7 J

Work done: w = -PΔ V = -2 × 0.5 × 101.325 = -101.325 J . Given q = 1200 J , Δ U = q + w = 1200 - 101.325 = 1098.68 ≈ 1098.7 J .

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