Practice question
Question
A closely wound solenoid of 2000 turns and the area of cross-section 1.5 × 10 –4 m 2 carries a current of 2.0 A. It is suspended through its center and perpendicular to its length, allowing it to turn in a horizontal plane in a uniform magnetic field 5 × 10 –2 tesla making an angle of 30º with the axis of the solenoid. The torque on the solenoid will be
Explanation
Magnetic moment M=NIA=2000*1.5e-4*2=0.6 Am^2, torque τ=MB sinθ.
Discussion
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