Practice question

Given: A circuit has a 12 V battery with 3 Ω internal resistance and two resistors 6 Ω and 3 Ω in parallel. What is the total current? These values define the system as per NCERT data. Formula: Parallel resistance: 1/R_p = 1/6 + 1/3 = 1 + 2/6 = 3/6 = 0.5 Rightarrow R_p = 2 Ω. This is standard NCERT relation. Substitution & Calculation: Total resistance: R_{total = 3 + 2 = 5 Ω . Current: I = fracvarepsilonR_{total = 12/5 = 2.4 A . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.