Practice question
Question
A charge particle of charge 25 × 10 -10 C is placed at a point. Find the magnitude of electric potential at a point which is at a distance of 5 m from the charge particle.
Explanation
V=kq/r=9e9*25e-10/0.05=45 V approx per V=kq/r.
Discussion
Comments
Please log in to join the discussion.
Login to commentNo comments yet. Be the first to start the discussion.