Practice question
Question
A block of mass 1kg moves on a rough surface with initial speed 4m/s. A retarding force F\=−0.8xN acts from x\=0.2m to x\=2m. What is the final speed?
Explanation
Initial K=12×1×42=8J. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 8 J as the result, so option A is correct.
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