Practice question

Given: A ball is thrown horizontally at 6 m/s from a height of 4.9 m . What is its horizontal range? (Take g = 9.8 m/s² ) Formula: Time to fall: h = 1/2 g t² Rightarrow 4.9 = 1/2 × 9.8 × t² Rightarrow 4.9 = 4.9 t² Rightarrow t² = 1 Rightarrow t = 1 s. Substitution & Calculation: Horizontal range R = v_x t = 6 × 1 = 6 m . Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.