#moles of gas

A gas has a Henry’s law constant of 250 bar. If its partial pressure is 5 bar and the solvent mass is 1 kg, what is the

p = KH · x . x = (5/250) = 0.02 . Molality ≈ x for dilute solutions, so m = 0.02 mol/kg . Moles = 0.02 × 1 = 0.02 mol .

Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Colligative Properties - Relative Lowering and Elevation of Boiling Point