Practice question
Question
A gas has a Henry’s law constant of 250 bar. If its partial pressure is 5 bar and the solvent mass is 1 kg, what is the number of moles of gas dissolved?
Explanation
p = KH · x . x = (5/250) = 0.02 . Molality ≈ x for dilute solutions, so m = 0.02 mol/kg . Moles = 0.02 × 1 = 0.02 mol .
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