For Hg₂Cl₂(s) Hg₂²⁺(aq) + 2Cl-(aq) , Ksp = 1.3 × 10⁻¹⁸ . What is [Hg₂²⁺] in a 0.01 M NaCl solution?
Ksp = [Hg₂²⁺][Cl-]² = 1.3 × 10⁻¹⁸ , [Cl-] ≈ 0.01 , [Hg₂²⁺] (0.01)² = 1.3 × 10⁻¹⁸ , [Hg₂²⁺] = (1.3 × 10⁻¹⁸/0.0001) = 1.3 × 10⁻¹⁴ M .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Homogeneous and Heterogeneous Equilibria and Applications of Equilibrium Constant