Practice question
Question
For Hg₂Cl₂(s) <=> Hg₂²⁺(aq) + 2Cl-(aq) , Ksp = 1.3 × 10⁻¹⁸ . What is [Hg₂²⁺] in a 0.01 M NaCl solution?
Explanation
Ksp = [Hg₂²⁺][Cl-]² = 1.3 × 10⁻¹⁸ , [Cl-] ≈ 0.01 , [Hg₂²⁺] (0.01)² = 1.3 × 10⁻¹⁸ , [Hg₂²⁺] = (1.3 × 10⁻¹⁸/0.0001) = 1.3 × 10⁻¹⁴ M .
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