The angular momentum of an electron in the fifth orbit of Be³⁺ is 5.275 × 10⁻³⁴ J s. What is its radius? (h = 6.626 × 10
n = 5. For Be³⁺ (Z=4), r₅ = 25/4 × 5.29×10⁻¹¹ = 3.306×10⁻¹⁰ m.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Developments Leading to Bohr Model - Electromagnetic Radiation and Spectrum