Practice question
Question
The angular momentum of an electron in the fifth orbit of Be³⁺ is 5.275 × 10⁻³⁴ J s. What is its radius? (h = 6.626 × 10⁻³⁴ J s, r₁ for H = 5.29 × 10⁻¹¹ m)
Explanation
n = 5. For Be³⁺ (Z=4), r₅ = 25/4 × 5.29×10⁻¹¹ = 3.306×10⁻¹⁰ m.