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#ammonia

12 public questions tagged with this topic.

Ionic Equilibrium - Acids Bases and pH and Ionization of Weak Acids Bases

For N₂(g) + 3H₂(g) 2NH₃(g) , Kp = 4.0 × 10⁻³ at 600 K. If 1 mole of N₂ and 3 moles of H₂ are in a 2 L vessel, what is PN

Initial: PN₂ = (1 × 0.0831 × 600/2) = 24.93 bar , PH₂ = 74.79 bar . Let 2x be PNH₃ , PN₂ = 24.93 - x , PH₂ = 74.79 - 3x . Kp = ((PNH₃)²/PN₂ (PH₂)³) = ((2x)²/(24.93 - x)(74.79 - 3x)³) = 4.0 × 10⁻³ . Solving, x ≈ 0.8 , PNH₃ = 2 × 0.8 = 1.6 bar .

Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Ionic Equilibrium - Acids Bases and pH and Ionization of Weak Acids Bases

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Laws of Chemical Combination - Conservation Mass Definite Multiple

A mixture of 4 g H₂ and 56 g N₂ is used to synthesize NH₃. What is the maximum mass of NH₃ produced? (Molar masses: H₂ =

Reaction: N₂ + 3H₂ → 2NH₃. Moles: H₂ = 2 mol, N₂ = 2 mol. H₂ limits. 2 mol H₂ reacts with (2/3) mol N₂, producing (4/3) mol NH₃ = (4/3) × 17 ≈ 22.67 g.

Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Laws of Chemical Combination - Conservation Mass Definite Multiple

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