Practice question
Question
A mixture of 4 g H₂ and 56 g N₂ is used to synthesize NH₃. What is the maximum mass of NH₃ produced? (Molar masses: H₂ = 2 g/mol, N₂ = 28 g/mol, NH₃ = 17 g/mol)
Explanation
Reaction: N₂ + 3H₂ → 2NH₃. Moles: H₂ = 2 mol, N₂ = 2 mol. H₂ limits. 2 mol H₂ reacts with (2/3) mol N₂, producing (4/3) mol NH₃ = (4/3) × 17 ≈ 22.67 g.
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