Practice question
Question
In projectile motion, what is the direction of the velocity vector at the highest point of its trajectory?
Explanation
Projectile motion splits into horizontal uniform and vertical accelerated motion per NCERT Chapter 4. Range R=u²sin2θ/g and max height H=u²sin²θ/2g. Using given u, θ, g, calculation yields Horizontal. Hence option A satisfies projectile formulas.