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Practice question

MCQ

Question

A particle moves in the x-y plane with a constant acceleration of (2 î + 3 ĵ) m/s². If it starts from rest at the origin, what is its speed after 2 s?

Options

Choose one · Correct answer highlighted

Explanation

Velocity is given by v = v₀ + at, where v₀ = 0 (starts from rest). As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 7.21 m/s as the result, so option A is correct.

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