Practice question
Question
A particle moves in a circular path of radius 1m completing 3 revolutions in 6s. What is its centripetal acceleration?
Explanation
Frequency f=nt=36=0.5Hz. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 0.5 Hz as the result, so option A is correct.