Practice question
Question
A hydraulic lift raises a 1800kg load using a small piston of radius 3cm and a large piston of radius 15cm. What force is applied on the small piston? (Take g\=9.8m/s2)
Explanation
F1 = A1A2F2, F2 = 1800×9.8 = 17640N. A1 = π(0.03)2, A2 = π(0.15)2, A1A2 = 0.00090.0225 = 125. F1 = 1764025 = 705.6N≈706N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 706 N. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
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