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Question

A gas occupies 3L at 47∘C and 1.5atm. What will be its volume if the temperature drops to −23∘C and pressure increases to 3atm?

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Explanation

Given: V1 = 3L, T1 = 47∘C = 320K, P1 = 1.5atm, T2 = −23∘C = 250K, P2 = 3atm. P1V1T1 = P2V2T2. V2 = V1×P1P2×T2T1 = 3×1.53×250320 = 3×0.5×0.78125 = 1.171875L≈1.17L.

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