Practice question
Question
A gas at 67∘C and 1.6atm occupies 8L. If the temperature is reduced to 17∘C and volume adjusted to 6L, what is the final pressure?
Explanation
Given: T1 = 67∘C = 340K, P1 = 1.6atm, V1 = 8L, T2 = 17∘C = 290K, V2 = 6L. Ideal gas law: P1V1T1 = P2V2T2. P2 = P1×V1V2×T2T1 = 1.6×86×290340. P2 = 1.6×1.3333×0.8529≈1.82atm.
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