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Question

A gas at 17∘C and 2.5atm occupies 5L. If the temperature is raised to 67∘C and the volume is adjusted to 7L, what is the final pressure?

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Explanation

Given: T1 = 17∘C = 290K, P1 = 2.5atm, V1 = 5L, T2 = 67∘C = 340K, V2 = 7L. Ideal gas law: P1V1T1 = P2V2T2. P2 = P1×V1V2×T2T1 = 2.5×57×340290. P2 = 2.5×0.7143×1.1724≈2.09atm.

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