Practice question
Question
A force F\=4i^−6j^N acts at r\=5i^+2j^m. What is the magnitude of the torque about the origin?
Explanation
τ = r×F = |i^j^k^5204−60| = k^(5×(−6)−2×4) = k^(−30−8) = −38k^Nm. Magnitude = 38Nm. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 38 Nm. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.