Practice question
Question
A 8kg block at 14m/s encounters a force F\=−3xN from x\=1.2m to x\=6m. What is the final speed?
Explanation
Initial K=12×8×142=784J. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 784 J as the result, so option A is correct.