#water freezing

Calculate Δ Ssurr when 2 mol of water freezes at 273 K if Δ Hfus = 6.01 kJ/mol.

For freezing, Δ H = -n × Δ Hfus = -2 × 6.01 = -12.02 kJ, Δ Ssurr = -Δ H / T = -(-12.02 × 10³) / 273 = 44.03 J/K.

Ref: NCERT Class 11 Chemistry > Chapter 5: Thermodynamics > Topic: Thermodynamic Terms - System Surroundings and Types of Systems