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#sulphur estimation

3 public questions tagged with this topic.

In the estimation of sulphur, 0.15 g of an organic compound gave 0.505 g of BaSO₄. What is the percentage of sulphur?

Molar mass of BaSO₄ = 233 g/mol, S = 32 g/mol. Mass of S = (32/233) × 0.505 = 0.069 g. Percentage = (0.069/0.15) × 100 = 46%.

Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Qualitative and Quantitative Analysis - Lassaigne Test and Estimation

In the estimation of sulphur, 0.25 g of a compound gave 0.583 g of BaSO₄. What is the percentage of sulphur?

Molar mass of BaSO₄ = 233 g/mol, S = 32 g/mol. Mass of S = (32/233) × 0.583 = 0.08 g. Percentage = (0.08/0.25) × 100 = 32%.

Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Qualitative and Quantitative Analysis - Lassaigne Test and Estimation