A proton has a de Broglie wavelength of 1.5 × 10⁻¹² m. What is its kinetic energy? (h = 6.626 × 10⁻³⁴ J s, mₚ = 1.67 × 1
v = h/(mλ) = 2.645×10⁵ m s⁻¹. KE = ½mv² = 5.837×10⁻¹⁷ J.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Quantum Mechanical Model - de Broglie Heisenberg and Schrodinger