139 public questions tagged with this topic.
2-Methylpropan-2-ol ((CH₃)3COH) dehydrates with conc. H₂SO₄ to form 2-methylpropene (CH₂=C(CH₃)CH₃), following Saytzeff’s rule.
Ref: NCERT Class 12 Chemistry > Chapter 7: Alcohols, Phenols and Ethers > Topic: Chemical Reactions of Phenols and Ethers and Uses
Phenol reacts with CHCl₃ and aqueous NaOH in the Reimer-Tiemann reaction to form salicylaldehyde (2-hydroxybenzaldehyde) via electrophilic substitution at the ortho position.
Ref: NCERT Class 12 Chemistry > Chapter 7: Alcohols, Phenols and Ethers > Topic: Chemical Reactions of Phenols and Ethers and Uses
Propan-2-ol (CH₃CH(OH)CH₃), a secondary alcohol, forms a secondary carbocation with Lucas reagent (ZnCl₂ in conc. HCl), causing turbidity in 5–10 minutes.
Ref: NCERT Class 12 Chemistry > Chapter 7: Alcohols, Phenols and Ethers > Topic: Chemical Reactions of Phenols and Ethers and Uses
In the Reimer-Tiemann reaction, phenol reacts with CHCl₃ and NaOH to form salicylaldehyde (C₆H₄(OH)CHO) after acidification.
Ref: NCERT Class 12 Chemistry > Chapter 7: Alcohols, Phenols and Ethers > Topic: Chemical Reactions of Phenols and Ethers and Uses
In Kolbe’s reaction, phenol reacts with CO₂ and NaOH under heat and pressure, followed by acidification, to form salicylic acid (2-hydroxybenzoic acid).
Ref: NCERT Class 12 Chemistry > Chapter 7: Alcohols, Phenols and Ethers > Topic: Chemical Reactions of Phenols and Ethers and Uses
The longest chain containing the -OH group has 4 carbons, so the base name is butane. The -OH is on the second carbon from the end nearest to it, so it is butan-2-ol.
Ref: NCERT Class 12 Chemistry > Chapter 7: Alcohols, Phenols and Ethers > Topic: Chemical Reactions of Phenols and Ethers and Uses
The compound has a 5-carbon chain with the -OH on the second carbon from the end nearest to it, named pentan-2-ol.
Ref: NCERT Class 12 Chemistry > Chapter 7: Alcohols, Phenols and Ethers > Topic: Chemical Reactions of Alcohols - Dehydration Oxidation Esterification
SOCl₂ converts 3-pentanol ( CH₃CH₂CHOHCH₂CH₃ ) to 3-chloropentane ( CH₃CH₂CHClCH₂CH₃ ) via substitution.
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Nature of C-X Bond and Methods of Preparation
In CH₃CH₂CHClCH₂CH₃ , the Cl-bearing carbon (C₃) is bonded to C₂, Cl, C₄, and one H, so it has 1 hydrogen.
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Nature of C-X Bond and Methods of Preparation
Bond strength decreases as halogen size increases due to weaker overlap: CH₃F > CH₃Cl > CH₃Br > CH₃I .
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Nature of C-X Bond and Methods of Preparation
Bond length increases with the size of the halogen. Among F, Cl, Br, and I, iodine is the largest, so CH₃-I has the longest C-X bond.
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Nature of C-X Bond and Methods of Preparation
KNO₂ substitutes Cl via SN₂ , forming CH₃CH₂CH₂ONO (propyl nitrite), as NO₂⁻ bonds through oxygen.
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Nature of C-X Bond and Methods of Preparation
