In the Dumas method, 0.3 g of a compound gave 70 mL of N₂ at STP. What is the percentage of nitrogen?
Mass of N = (28/22400) × 70 = 0.0875 g. Percentage = (0.0875/0.3) × 100 ≈ 29.17% ≈ 29%.
Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Qualitative and Quantitative Analysis - Lassaigne Test and Estimation