3 public questions tagged with this topic.
Kw = Ka × Kb = 1.0 × 10⁻¹⁴ , Kb = (1.0 × 10⁻¹⁴/6.2 × 10⁻¹⁰) ≈ 1.61 × 10⁻⁵ .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Relationship Between Kp Kc and Factors Affecting Equilibrium - Le Chatelier
Kw = Ka × Kb = 1.0 × 10⁻¹⁴ , so Kb = (Kw/Ka) = (1.0 × 10⁻¹⁴/4.9 × 10⁻¹⁰) ≈ 2.04 × 10⁻⁵ .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Physical Equilibrium - Solid-Liquid Gas-Liquid and Henry's Law
In HCN , carbon has 2 bonding domains (1 triple bond, 1 single bond), requiring sp hybridization, forming a linear shape.
Ref: NCERT Class 11 Chemistry > Chapter 4: Chemical Bonding and Molecular Structure > Topic: Valence Bond Theory and Hybridisation - sp sp2 sp3 dsp2
