5 public questions tagged with this topic.
Each ethane-1,2-diamine (en) is bidentate (2 donor atoms), and each H₂O is unidentate. In [Ni(en)2(H₂O)2]2+, 2 en (4 atoms) + 2 H₂O = 6.
Ref: NCERT Class 12 Chemistry > Chapter 5: Coordination Compounds > Topic: Werner's Theory and Definitions - Ligands Coordination Number
In [Cu(en)2]2+, each ethane-1,2-diamine (en) is bidentate, contributing 2 donor atoms. Total = 2 × 2 = 4.
Ref: NCERT Class 12 Chemistry > Chapter 5: Coordination Compounds > Topic: Werner's Theory and Definitions - Ligands Coordination Number
In [Co(NH₃)4(en)]3+, 4 NH₃ provide 4 N atoms, and 1 en (bidentate) provides 2 N atoms. Total = 4 + 2 = 6.
Ref: NCERT Class 12 Chemistry > Chapter 5: Coordination Compounds > Topic: Nomenclature of Coordination Compounds
[Co(en)3]3+ contains 3 ethane-1,2-diamine (en) ligands, a bidentate ligand denoted as H₂NCH₂CH₂NH₂.
Ref: NCERT Class 12 Chemistry > Chapter 5: Coordination Compounds > Topic: Colour and Magnetic Properties and Stability and Importance
[Ni(en)2]2+ (Ni₂+, d8) with 2 bidentate en (4 donor atoms) is square planar, using dsp2 hybridization.
Ref: NCERT Class 12 Chemistry > Chapter 5: Coordination Compounds > Topic: Bonding - Valence Bond Theory and Hybridisation
