4 public questions tagged with this topic.
In 2Al + 3Cl₂ → 2AlCl₃, Al (0) loses electrons to become Al₃+ (+3).
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Electrode Potential and Electrochemical Series and Galvanic Cells
Aluminum (Al) has [Ne] 3s² 3p¹ . Losing 3 electrons forms Al³⁺ with [Ne] , a noble gas configuration.
Ref: NCERT Class 11 Chemistry > Chapter 4: Chemical Bonding and Molecular Structure > Topic: Ionic Bonding - Lattice Enthalpy and Properties of Ionic Compounds
Calcium (Ca) has the configuration [Ar] 4s² . Losing 2 electrons forms Ca²⁺ with a stable noble gas configuration [Ar] .
Ref: NCERT Class 11 Chemistry > Chapter 4: Chemical Bonding and Molecular Structure > Topic: Hydrogen Bonding and Resonance and Dipole Moment
Third ionization enthalpy is highest for B (removing an electron from B²⁺ with 1s²) due to its small size and stable configuration, compared to Al, Ga, or In.
Ref: NCERT Class 11 Chemistry > Chapter 3: Classification of Elements and Periodicity in Properties > Topic: Periodic Trends - Atomic Radii Ionic Radii and Ionization Enthalpy
