#de Broglie wavelength

Quantum Mechanical Model - de Broglie Heisenberg and Schrodinger

The velocity of an electron in the second orbit of a hydrogen atom is 1.095 × 10⁶ m s⁻¹. What is its de Broglie waveleng

λ = h/(mv) = 6.65×10⁻¹⁰ m.

Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Quantum Mechanical Model - de Broglie Heisenberg and Schrodinger

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Quantum Mechanical Model - de Broglie Heisenberg and Schrodinger

An electron and an alpha particle have the same de Broglie wavelength. What is the ratio of their velocities? (mₑ = 9.1

vₑ/v_α = m_α/mₑ ≈ 7297.

Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Quantum Mechanical Model - de Broglie Heisenberg and Schrodinger

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Quantum Mechanical Model - de Broglie Heisenberg and Schrodinger

An electron in the third orbit of a hydrogen atom has a velocity of 7.3 × 10⁵ m s⁻¹. What is its de Broglie wavelength?

λ = h/(mv) ≈ 9.98×10⁻¹⁰ m.

Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Quantum Mechanical Model - de Broglie Heisenberg and Schrodinger

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Quantum Mechanical Model - de Broglie Heisenberg and Schrodinger

The de Broglie wavelength of a particle is 6.626 × 10⁻¹⁰ m. If its mass is 1.0 × 10⁻³⁰ kg, what is its velocity? (h = 6.

v = h/(mλ) = 1.0×10⁶ m s⁻¹.

Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Quantum Mechanical Model - de Broglie Heisenberg and Schrodinger

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Quantum Mechanical Model - de Broglie Heisenberg and Schrodinger

A neutron and a proton have the same de Broglie wavelength. What is the ratio of their velocities? (mₚ = 1.67 × 10⁻²⁷ kg

Since mₚ = mₙ, vₚ/vₙ = 1.

Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Quantum Mechanical Model - de Broglie Heisenberg and Schrodinger

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Quantum Mechanical Model - de Broglie Heisenberg and Schrodinger

A proton has a de Broglie wavelength of 2.0 × 10⁻¹² m. What is its kinetic energy? (h = 6.626 × 10⁻³⁴ J s, mₚ = 1.67 × 1

v = h/(mλ). KE = ½mv² = 3.29×10⁻¹⁷ J.

Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Quantum Mechanical Model - de Broglie Heisenberg and Schrodinger

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Quantum Mechanical Model - de Broglie Heisenberg and Schrodinger

An alpha particle and a proton have the same kinetic energy. What is the ratio of their de Broglie wavelengths? (mₚ = 1.

λ_α/λₚ = √(mₚ/m_α) ≈ 0.501.

Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Quantum Mechanical Model - de Broglie Heisenberg and Schrodinger

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Quantum Mechanical Model - de Broglie Heisenberg and Schrodinger

An electron in Li²⁺ has a de Broglie wavelength of 2.21 × 10⁻¹⁰ m in the second orbit. What is its kinetic energy? (h =

v = h/(mλ). KE = ½mv² = 4.936×10⁻¹⁸ J.

Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Quantum Mechanical Model - de Broglie Heisenberg and Schrodinger

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Quantum Mechanical Model - de Broglie Heisenberg and Schrodinger

A neutron has a de Broglie wavelength of 3.0 × 10⁻¹² m. What is its kinetic energy? (h = 6.626 × 10⁻³⁴ J s, mₙ = 1.67 ×

v = h/(mλ). KE = ½mv² = 1.457×10⁻¹⁷ J.

Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Quantum Mechanical Model - de Broglie Heisenberg and Schrodinger

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Quantum Mechanical Model - de Broglie Heisenberg and Schrodinger

A photon of wavelength 250 nm strikes a metal surface. The ejected electron has a de Broglie wavelength of 1.0 × 10⁻⁹ m.

E = hc/λ ≈ 7.951×10⁻¹⁹ J. KE = h²/(2mλ²) ≈ 2.412×10⁻¹⁹ J. W₀ = E - KE ≈ 5.539×10⁻¹⁹ J.

Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Quantum Mechanical Model - de Broglie Heisenberg and Schrodinger

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Quantum Mechanical Model - de Broglie Heisenberg and Schrodinger

A proton and an alpha particle have the same de Broglie wavelength. What is the ratio of their velocities? (mₚ = 1.67 ×

mₚ vₚ = m_α v_α. vₚ/v_α = m_α/mₚ ≈ 4.

Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Quantum Mechanical Model - de Broglie Heisenberg and Schrodinger

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Quantum Mechanical Model - de Broglie Heisenberg and Schrodinger

A proton has a de Broglie wavelength of 1.5 × 10⁻¹² m. What is its kinetic energy? (h = 6.626 × 10⁻³⁴ J s, mₚ = 1.67 × 1

v = h/(mλ) = 2.645×10⁵ m s⁻¹. KE = ½mv² = 5.837×10⁻¹⁷ J.

Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Quantum Mechanical Model - de Broglie Heisenberg and Schrodinger

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