9 public questions tagged with this topic.
Kp = Kc (RT)Δ n , Δ n = 1 - 2 = -1 , RT = 0.0831 × 350 ≈ 29.085 . Thus, Kc = Kp × RT = 4.0 × 29.085 ≈ 116.34 .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Buffer Solutions and Solubility Product and Common Ion Effect
For PbI₂ Pb²⁺ + 2I- , [Pb²⁺] = 1.0 × 10⁻⁴ , [I-] = 0.05 + 2 × 1.0 × 10⁻⁴ ≈ 0.05 M . Ksp = [Pb²⁺][I-]² = (1.0 × 10⁻⁴) (0.05)² = 2.5 × 10⁻⁷ .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Buffer Solutions and Solubility Product and Common Ion Effect
CaF₂ Ca²⁺ + 2F⁻ , Ksp = [Ca²⁺][F⁻]² = S (2S)² = 4S³ = 1.0 × 10⁻⁶ . Solving, S³ = 2.5 × 10⁻⁷ , S ≈ 6.3 × 10⁻³ .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Buffer Solutions and Solubility Product and Common Ion Effect
For PbCl₂ Pb²⁺ + 2Cl- , Ksp = [Pb²⁺][Cl-]² = 1.7 × 10⁻⁵ . Let solubility = S , [Cl-] = 0.1 + 2S ≈ 0.1 , S (0.1)² = 1.7 × 10⁻⁵ , S = (1.7 × 10⁻⁵/0.01) = 1.7 × 10⁻³ M .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Buffer Solutions and Solubility Product and Common Ion Effect
For Ag₂SO₄ 2Ag+ + SO₄²⁻ , [Ag+] = 2 × 5.0 × 10⁻⁵ = 1.0 × 10⁻⁴ , [SO₄²⁻] = 0.1 + 5.0 × 10⁻⁵ ≈ 0.1 . Ksp = (1.0 × 10⁻⁴)² × 0.1 = 1.0 × 10⁻⁹ .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Buffer Solutions and Solubility Product and Common Ion Effect
For BaSO₄ Ba²⁺ + SO₄²⁻ , [Ba²⁺] = 2.0 × 10⁻⁹ , [SO₄²⁻] ≈ 0.05 , Ksp = (2.0 × 10⁻⁹) × 0.05 = 1.0 × 10⁻¹⁰ .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Buffer Solutions and Solubility Product and Common Ion Effect
K⁺ has 18 electrons.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Quantum Numbers - Principal Azimuthal Magnetic Spin
For n=3, l max = 2. l=3 is invalid.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Quantum Numbers - Principal Azimuthal Magnetic Spin
Shortest wavelength (highest energy) for n=5 to n=1.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Quantum Numbers - Principal Azimuthal Magnetic Spin
