In the estimation of carbon, 0.25 g of an organic compound produced 0.66 g of CO₂. What is the percentage of carbon in t
Mass of C = (12/44) × 0.66 = 0.18 g. Percentage = (0.18/0.25) × 100 = 72%.
Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Isomerism - Structural Isomerism - Chain Position Functional Metamerism