The angular momentum of an electron in the sixth orbit of Li²⁺ is 6.33 × 10⁻³⁴ J s. What is its radius? (h = 6.626 × 10⁻
n=6. For Li²⁺ (Z=3), r₆ = 36/3 × 5.29×10⁻¹¹ = 6.348×10⁻¹⁰ m.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Electronic Configuration - Aufbau Pauli Hund and Stability