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Moles = 27 / 27 = 1 mol, Δ T = 125 - 25 = 100 K, qv = nCvΔ T = 1 × 22.4 × 100 = 2240 J = 2.24 kJ.
Ref: NCERT Class 11 Chemistry > Chapter 5: Thermodynamics > Topic: Heat Capacity and Calorimetry and Measurement of Enthalpy
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