3 public questions tagged with this topic.
Excess NH₃ substitutes I in CH₃CH₂CH₂I to form CH₃CH₂CH₂NH₂ (propylamine) via SN₂ .
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Physical Properties - Boiling Point Dipole Moment Solubility
This is a Wurtz reaction, coupling two CH₃CH₂CH₂Cl molecules to form CH₃CH₂CH₂CH₂CH₂CH₃ (hexane).
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Elimination Reactions and Reaction with Metals and Other Reactions
NaOCH₂CH₃ substitutes Cl in CH₃CH₂CH₂Cl via SN₂ , forming CH₃CH₂CH₂OCH₂CH₃ (ethyl propyl ether).
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Elimination Reactions and Reaction with Metals and Other Reactions
