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Δ S = nR ln(V₂/V₁) = 1 × 8.314 × ln(5/20) = 8.314 × ln(0.25) = 8.314 × (-1.386) = -11.52 J/K.
Ref: NCERT Class 11 Chemistry > Chapter 5: Thermodynamics > Topic: Bond Enthalpy and Entropy and Spontaneity
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