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Question

A 0.78 g sample of a hydrocarbon produces 2.64 g of CO₂ and 0.54 g of H₂O on complete combustion. What is its molecular formula if its molar mass is 78 g/mol? (Atomic masses: C = 12, H = 1, O = 16)

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Explanation

Mass of C ≈ 0.72 g; mass of H = 0.06 g. Total = 0.78 g. Moles: C = 0.06, H = 0.06; ratio = 1 : 1; empirical formula = CH, mass = 13 g/mol. n = 78/13 = 6; molecular formula = C₆H₆.