Practice question
Question
What volume of O₂ at STP is required to burn 7.8 g of C₃H₆ completely to CO₂ and H₂O? (Molar mass: C₃H₆ = 42 g/mol)
Explanation
Reaction: 2C₃H₆ + 9O₂ → 6CO₂ + 6H₂O. Moles of C₃H₆ ≈ 0.1857 mol. 2 mol need 9 mol O₂; 0.1857 mol need ≈ 0.8357 mol. Volume = 0.8357 × 22.4 ≈ 18.72 L.
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