Practice question
Question
What is the mass of BaCl₂ produced when 26.1 g of Ba(OH)₂ reacts with excess HCl? (Molar masses: Ba(OH)₂ = 171 g/mol, BaCl₂ = 208 g/mol)
Explanation
Reaction: Ba(OH)₂ + 2HCl → BaCl₂ + 2H₂O. Moles of Ba(OH)₂ = 26.1/171 ≈ 0.1526 mol. 1 mol Ba(OH)₂ produces 1 mol BaCl₂; mass = 0.1526 × 208 ≈ 31.74 g.
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