Practice question
Question
What is the boiling point elevation of a solution containing 10 g of fructose (molar mass = 180 g/mol) in 400 g of water? ( Kb = 0.52 K kg mol⁻¹ )
Explanation
Moles of fructose = (10/180) ≈ 0.0556 mol . Molality = (0.0556/0.4) ≈ 0.139 mol/kg . Δ Tb = 0.52 × 0.139 ≈ 0.0723 K .
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