Skip to content

Question

The wavenumber of the fourth line in the Balmer series of a hydrogen atom is: (RH = 1.097 × 10⁷ m⁻¹)

Options

Choose one · Correct answer highlighted

Explanation

Balmer: n₁=2, n₂=6. ν̄ = 2.437×10⁶ m⁻¹.