Practice question
Question
For 2P(g) <=> Q(g) , if Kp = 0.1 at 500 K ( R = 0.0831 bar L/mol K ), what is Kc ?
Explanation
Kp = Kc (RT)Δ n , Δ n = 1 - 2 = -1 , RT = 0.0831 × 500 = 41.55 . Thus, Kc = Kp × RT = 0.1 × 41.55 = 4.155 .
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