Practice question
Question
A solution of 0.03 mole of a non-volatile solute in 300 mL of water has an osmotic pressure of 1.231 atm at 27°C. What is the van’t Hoff factor? ( R = 0.0821 L atm mol⁻¹ K⁻¹ )
Explanation
Pi = i · M · RT . Molarity = (0.03/0.3) = 0.1 M . 1.231 = i × 0.1 × 0.0821 × 300 . i = (1.231/0.1 × 24.63) ≈ 0.5 , recalculate: i = 1 (non-electrolyte).
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