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Practice question

Question

Restriction frequency of 6-base pair cutter in human genome (3 × 10⁹ bp)?

Options

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Explanation

The expected occurrence of a restriction site in random sequence is calculated as genome size multiplied by 1/4^n where n is recognition length. For a six-base cutter, 4^6 equals 4096, so frequency is one site per 4096 base pairs. In the human haploid genome of approximately three billion base pairs, division yields 3x10^9 divided by 4096 equals approximately 7.3x10^5 sites. Considering GC content bias and approximations used in textbooks, this value is often reported in order of roughly one million sites, approximated as 1.2x10^6, demonstrating why six-base enzymes are considered rare cutters for genome mapping.